04-29-2024, 06:20 PM
I'm working on a bash script where I need to manipulate dates, but I'm having trouble formatting the date output as I need it. The default $(date) command outputs the full date string, which includes the day of the week, month, day, time, timezone, and year. This is far more information than I require for my script, and it causes unnecessary complication for my use case.
Specifically, I need the date formatted as YYYY-MM-DD. From what I've found in the man pages and various forums, the date command can be formatted with different options, but I'm not clear on the exact syntax to achieve the format I want.
Here's what the default date command gives me:
The result is something like this: Tue Mar 14 15:20:13 PDT 2023
Can anyone provide me with the correct formatting options for the date command to get the date in YYYY-MM-DD format?
Specifically, I need the date formatted as YYYY-MM-DD. From what I've found in the man pages and various forums, the date command can be formatted with different options, but I'm not clear on the exact syntax to achieve the format I want.
Here's what the default date command gives me:
Code:
date_output = $(date)
echo $date_output
The result is something like this: Tue Mar 14 15:20:13 PDT 2023
Can anyone provide me with the correct formatting options for the date command to get the date in YYYY-MM-DD format?